The radius of the top and bottom of a bucket of slant height 35 cm are 25 cm and 8cm. The curved surface of the bucket is: *
(a)4000 sq.cm
(b)3500 sq.cm
(c)3630 sq..cm
(d)3750 sq.cm
Answers
Answered by
3
Answer:
Answer. => 22 × 45×35 /7 = 34650/7 = 4950 cm².
Answered by
8
Answer:
c) 3630
Step-by-step explanation:
curved surface area of bucket =π(R1 +R2)×L
curved surface area of bucket =π(R1 +R2)×L = 22/7×(25+8)×35
=22×33×5
=3630sq. cm
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