Question

The radius of the wheel of the car is 0.4 m. The car is accelerated from rest by an angular acceleration of 1.5 rad s^-2 for 20 s. How much distance the wheel covers in this time interval and what will be its linear velocity?

Answer 1

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Answer 2

Explanation:

Given The radius of the wheel of the car is 0.4 m. The car is accelerated from rest by an angular acceleration of 1.5 rad s^-2 for 20 s. How much distance the wheel covers in this time interval and what will be its linear velocity?

• Radius of wheel r = 0.4 m
• Angular acceleration α = 1.5 rad / sec^2
• Time t = 20 secs
• Initial angular speed of the wheel wo = 0 rad/sec
• So equation of motion will be  
•                 Theta = Wo t + ½ αt^2
•                           = 0 + ½ x 1.5 x 20 x 20
•                           = 300 rad
• We need to find the distance covered by the wheel.
• So if theta = 2π then distance s = 2πr
• So for theta = 300 rad,  distance s = 300 x r
•                                                      = 300 x 0.4
•                                                     = 120 m
• Linear velocity V = r ω
• Now we have ω = ωo + αt
•                           = 0 + 1.5 x 20
•                           = 30 rad / sec
•                Or V = 0.4 x 30
•                     V = 12 m/s

Reference link will be

https://brainly.in/question/7041889