the radius of theclosed cylinder is 7cm and its total surface area is 528cm^2.find the height of the cylinder
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t.s.a of cylinder = 2πr(h+r)
528 = 2 x 22/7 x 7 (h+7)
528 = 44h + 308
44h = 528 - 308 = 220
h = 220/44 = 5 cm
528 = 2 x 22/7 x 7 (h+7)
528 = 44h + 308
44h = 528 - 308 = 220
h = 220/44 = 5 cm
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area of total surface of cylinder = 2πr(r+h)
528 = [2×(22/7)×7] [7+h]
528 = (44)(7+h)
528 = 308 + 44h
528 - 308 = 44h
220 = 44h
220/44 = h
5 = h
h=5 cm
this is your answer.....
528 = [2×(22/7)×7] [7+h]
528 = (44)(7+h)
528 = 308 + 44h
528 - 308 = 44h
220 = 44h
220/44 = h
5 = h
h=5 cm
this is your answer.....
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