Question

The radius of third orbit of Heion
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Answer 1

Answer:

the basic formula for calculating the radius of nth orbit is Rn=0.529×(n^2/Z)angstrom where Z is the atomic number of the element.

Explanation:

Hope it helps you

Answer 2

Conclusion

Bohr's Orbit

According to the Bohr model, electrons in atoms are in various energy orbits around the nucleus (think of planets orbiting around the sun). Bohr developed the term energy levels to describe these circles of varied energy (or shells).

Main content

Radius of Bohr's Orbit = ×$\frac{0.529 \times n^2}{Z} A^o$

Where

$n$ = Principal quantum number of orbit.

$Z$ = Atomic number.

$3^{rd}$ Shell of $He^+$ means $n=3$

$Z$ for $He^+$ is $Z=2$

Substituting the above values in the given formula

We get,

$\rightarrow \frac{0.529 \times 3^2}{2} A^o$

there for, Radius of $3^{rd}$ Shell of $He^+$ is

$2.3805 A^o$

To learn more about Bohr's Orbit

https://brainly.in/question/38415785

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