The radius of third orbit of hydrogen atom using bohr’s radius
a = 0.529*A
Answers
Answered by
1
the formulae of any radius of an orbit is = 0.529xn^2/z.
so the radius of the third orbit of hydrogen is = 0.529x3^2/1=4.761 Å. .where n= no of orbit and z= atomic number.
Answered by
0
R=0.529×n²/z
R=0.529×9
R=4.761 Å
Similar questions