Question

The radius of Tl^(+) is 164pm and radius of O^(2-) is 126pm .Predict the coordination number of O^(2) - in Tl_(2)O .(a) 4 (b) 2 (c) 8 (d) 12​

Answer 1

Answer:

87o9ow(£)£(393+_84(493(302(202(303(393=1

Answer 2

Given: Radius of cation is 164 pm

            Radius of cation is 126 pm.

To Find: Coordination number of oxide ion

Explanation:

The coordination number of ion in any compound can be calculated by the ratio of size of cation to  size of anion.

radius of cation = $r^{+}$

radius of anion= $r^{-}$

if the ratio lies is less than 0.225 then coordination number is 2

0.225-0.414 : coordination number would be 4

Ratio 0.414 - 0.732 : CN 6

Ratio 0.732- 1.000 : CN 8

$Tl^{+} = 164 pm\\O^{-2} = 126 pm$

$\frac{r^{+} }{r^{-} } = \frac{164}{126} = 1.3015$

Ratio is 1.3015 hence coordination number is 2