The radius of two circles are 19 cm and 9 cm respectively.Find the radius of the circle which has circumference equal to the sum of the circumferences of the two circles
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r=19
circumference=2 x 22/7 x 19
=44/7 x 19 = 836/7
r= 9
circumference=2 x 22/7 x 9
=44/7 x 9 = 396/7
sum of circumferences = 836/7 +396/7
= 1232/7
1232/7 = 2 x 22/7 x r
1232 = 44r
1232/44 = r
28 = r
circumference=2 x 22/7 x 19
=44/7 x 19 = 836/7
r= 9
circumference=2 x 22/7 x 9
=44/7 x 9 = 396/7
sum of circumferences = 836/7 +396/7
= 1232/7
1232/7 = 2 x 22/7 x r
1232 = 44r
1232/44 = r
28 = r
Answered by
5
Answer ✅✅✅
radius of first circle = 19 CM
circumference of first circle = 2πr1
radius of second circle = 9cm
circumference of second circle =2πr2
now
circumference of both circle=2πr1+2πr2
= 2π(r1+r2)
=2 ×22/7 (19+9)
=2×22/7 (28)
= 2×22×4
= 176cm
Since circumference of both circle = circumference of bigger circle
2πr = 176cm
2×22/7×r = 176cm
44/7 r =176
r= 176 × 7
—
44
r= 28 cm
Hence the radius of bigger circle= 28cm.
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