Question

The radius of which of the following orbit is same
as that of second Bohr's orbit of hydrogen atom?
(1) He+ (n = 4) (2) Be3+ (n = 4)
(3) Li2+ (n = 3) (4) He+ (n = 2)​

Answer 1

Explanation:

I

H

=0.529

A

∘

→I

n

=I

H

×

Z

n

2

For Li

2+

(n=2),

I

Li

2+

=I

H

×

3

(2)

2

=

9

I

H

×4

For Li

2+

(n=3),

I

Li

2+

=I

H

×

3

(3)

3

=3r

H

For Be

3+

(n=2),

I

Be

3+

=I

H

×

4

(2)

2

=I

H

For He

+

(n=2),

I

He

+

=I

H

×

2

(2)

2

=2r

H

This, Be

3+

(n=2) has the same radius as that of the first Bohr's orbit of H− atom.

Answer 2

Answer:

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