Question

The radius
radius of
electrostatic force in meca to
air is 1:8, then what is the dielectric constant
​

Answer 1

Answer:

8:1

which class question

Answer 2

Answer:

given,

charge on the electron=1.6×10−19C

mass of the electron=9.1×10−31kg

gravitational constant=6.67×10−11Nm2kg−2

i)to find the electrostatic force b/w 2 electron.

let 2 electrons are at a distance 'd' apart 

the electrostatic force is Fe=4πεo1d2q2=d29×109×(1.6×10−19)2=d223.04×10−29N

ii) To find the gravitational force,

Fg=d2Gm2=d26.67×10−11×(9.1×10−31)2=d2553.56×