Question

The railway fare for 240 km of journey is rs 150 , what would be the fare for a journey of
139.2 km ? ​

Answer 1

Answer:

Let,

P(x) x+3=0

X= -3

Putting the value of x in eq

3x + kx +6 = 0

3 × -3 + k × -3 + 6 =0

-9 +(-3k) + 6= 0

-3 + (-3k) = 0

-3= +3k

K= -1 ans

$Let,P(x) x+3=0X= -3Putting the value of x in eq3x + kx +6 = 03 × -3 + k × -3 + 6 =0-9 +(-3k) + 6= 0-3 + (-3k) = 0-3= +3kK= -1 ans$

Step-by-step explanation:this only i know

Answer 2

Answer:

87rs

Step-by-step explanation:

The price of 240 kms in railway fare = 150

The price of 1 in railway fare = x

To find the value 150/240 = 0.625rs

Therefore price of 1 km = 0.625

--------------------------------

Now to find of 139.2 kms

price of 1 km= 0.625

price of 139.2 = 0.625 x 139.2 = 87rs

therefore price of 139.2 kms in railway fre is 87 rs