The rain appears to fall vertically with a speed of 3 m/s relative to a man standing on ground. Find the velocity of rain relative to the man when he moves towards east with a speed of 2 m/s (Take XY plane on ground)
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Let OP=3
i
^
be the velocity of man.
OQ
be the velocity of rain
PQ is the velocity of rain relative to man.
Case II:
OR
=6
i
^
is the new velocity of man.
RQ
= new velocity of rain relative to man OP=PR=PQ=3
Now OQ
2
=OP
2
+PQ
2
i.e, OQ
2
=3
2
+3
2
i.e, OQ=3
2
km h
−1
and tanθ=
OP
PQ
=
3
3
=1 i.e. θ=45
o
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