Question

The raise in the temperature of a given mass of an
ideal gas at constant pressure and at temperature
27° to double its volume is
(1) 327°C
(2) 54°C
(4) 600°C
(3) 300°C​

Answer 1

Answer:

327 is the correct answer.

mark as best. as your wish.

Answer 2

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Answer:

IDEAL GAS EQUATION...

PV=nRT

Now,

P1V1/T1=P2V2/T2

Here 'P' is constant so,

V1/T1=V2/T2

Given T1=27°c = 300k

Volume is double (v2/v1) =2

V1/V2=T1/T2

1/2=300/T2

T2=2X300

T2=600

T2=600-273

T2=327°c

Hence rise in temperature =327-27=300°c

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