Question

The raise in the temperature of a given mass of an ideal gas at constant pressure and at temperature 27° to double its volume is

Answer 1

The raise in temperature to double volume will be 300°C

Explanation :

From the Ideal gas law we know that,

$\frac{P1V1}{T1}  = \frac{P2V2}{T2}$

Please ignore the A^ in the formula

Since pressure is constant so we have,

V₁/T₁ = V₂/T₂

=> V₂/V₁ = T₂/T₁

Given temperature T₁ = 27°C = 273 + 27 = 300k

since volume becomes double so, V₂/V₁ = 2

Hence ,

T₂/300  = 2

=> T₂ = 600k = 327°C

Hence raise in temperature = 327-27 = 300°C

Answer 2

Answer:The raise in temperature to double volume will be 300°C