Math, asked by Aditya72779, 3 months ago

The random variable X has a probability
distribution P(X) of the following form,
where k is some number:
P(X) {k, if x = 0
2k, if x = 1
3k if x = 2
O other wise
(a) Determine the value of k.
(b) Find P (X <2), P (X s 2), P (X 2)..​

Answers

Answered by Anonymous
8

It is known that the sum of probabilities of a probability distribution of random variables is one.

∴k+2k+3k+0=1

⇒6k=1

</p><p>⇒k =  \frac{1}{6}

(b) P(X<2)=P(X=0)+P(X=1)

=k+2k

=3k

 =  \frac{3}{6}

 =  \frac{1}{2}

P(X≤2)=P(X=0)+P(X=1)+P(X=2)

=k+2k+3k

=6k

 =  \frac{6}{6}

= 1

P(X≥2)=P(X=2)+P(X>2)

=3k+0

=3k

 =  \frac{3}{6}

 \huge{ = \frac{1}{2} }

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