Question

The random variable X has a variance of 2.1

Let Y = 5X + 2.7

What is the variance of Y?

Give your answer to 1 decimal place.

Answer 1

Answer:

Let Y = 5× plus 2.7

=5.1 because x always 1

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Briliant Answer

Answer 2

Step-by-step explanation:

For a discrete random variable X, the variance of X is obtained as follows: var(X)=∑(x−μ)2pX(x), where the sum is taken over all values of x for which pX(x)>0. So the variance of X is the weighted average of the squared deviations from the mean μ, where the weights are given by the probability function pX(x) of X.