Question

the range and height of a projectile are equal and then angle of projectile with the horizontal is
​

Answer 1

Answer

R=

g

u

2

sin2θ

H=

2g

u

2

sin

2

θ

g

u

2

sin2θ

=

2g

u

2

sin

2

θ

2sinθcosθ=

2

sin

2

θ

ucosθ=sinθ

tanθ=4

θ=tan

−1

4

hope its helpful