Question

The range obtained is 50m.when the angle of projection is 15.what is the range when angle of projection is 750​

Answer 1

Answer:

100m

Explanation:

If it is fired with the same speed at an angle of 45^@ its range will be. 50=u2sin2×152gor u^2 /g = (50) /(sin 30^@) = (50)/(1//2) = 100R = 9u^2 sin 2 xx 45^2)/g = u^2/g = 100 m`.

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