The range of a particle when launched at an angle of
15° with the horizontal is 1.5 km. The range of
projectile when launched at an angle of 45° to the
horizontal will be
1.5 km
3 km
4.5 km
6 km
Answers
Answered by
5
3km
Range is directly proportional to Sin2theta
R1/R2 = Sin 30/Sin90
1.5/x = 1/2
X = 3km
Range is directly proportional to Sin2theta
R1/R2 = Sin 30/Sin90
1.5/x = 1/2
X = 3km
Similar questions