Question

The range
of a projectile is 24m and the
maximum height is 8m. Then what
will be the initial velocity and angle of projection​

Answer 1

Answer:

max. height/range=tan (theta)/4

so tan theta=3/4

theta=37*

initial velocity=(max. height×2×g/sin^2theta)^1/2=20m/s(approx.)

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