Question

The range of a projectile projected at an angle 15° with horizontal is 100 root3 m. I it is fired with the same speed at an angle of 60° with vertical, its range will be. Hai Kisi mein himmat yeh solve krne ki???

Answer 1

Concept:-Horizontal component of velocity is only responsible for the range

Solution:-Let the initial velocity of the projectile be v

horizontal component=vcos15°

Time taken to cover this range=2usin∅/g=2vsin15°/g

now,

vcos15°×2vsin15°/10=100√3

v^2sin30°/=100√3

v^2×1/2=100√3

v^2=200√3m

Range at an angle ∅=2v^2sin∅cos∅/g

Range at angle 60°=2×200√3×sin60°cos60°/10

=2×200√3×1/2 ×√3/2 ×1/10

=>600/20=30m

range will be 30m

Answer 2

Explanation:

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