Math, asked by arnavarn7, 11 months ago

the range of f(x)= sgn(2^x)+sgn( | x-5 |)=

Answers

Answered by Anonymous
1

Answer:

Step-by-step explanation:

As by definition

Sign(x) = { -1 x<0; 1 x>0; 0 x=0

Sign(x) = |x|/x = x/|x|

So similarly

Sign(x^2+1) = |x^2+1|/x^2+1 I.e. |x^2+1|>0

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Answered by DeviIQueen
10

As by definition

Sign(x) = { -1 x<0; 1 x>0; 0 x=0

Sign(x) = |x|/x = x/|x|

So similarly

Sign(x^2+1) = |x^2+1|/x^2+1 I.e. |x^2+1|>0

Attachments:
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