Question

The range of f(x) = sin–1x + cos–1x + sec–1x is

Answer 1

Answer:

here is your answer mate...

Step-by-step explanation:

The function f is defined for x = ±1

Now, f(1) = sin-1(1) + sec-1(1) + tan-1(1)

= π/2 + 0 + π/4 = 3π/4

Also, f(-1)= sin-1(-1) + sec-1(-1) + tan-1(-1)

= - π/2 + π - 0 - π/4

= 3π/4 Thus, Rf = {π/4, 3π/4}

plz plz plz mark me as brainliest plzz...

Answer 2

Answer:

The function f is defined for x = ±1

Now, f(1) = sin-1(1) + sec-1(1) + tan-1(1)

= π/2 + 0 + π/4 = 3π/4

Also, f(-1) = sin-1(-1) + sec-1(-1) + tan-1(-1)

= - π/2 + π - 0 - π/4

= 3π/4

Thus, Rf = {π/4, 3π/4}