Math, asked by anjanaminj2002, 8 months ago

The range of f(x)=x/1+x^2
Plz explain

Answers

Answered by ramshankar8693
0

Answer:

Given f(x)=2−∣x−5∣

Domain of f(x) is defined for all real values of x.

Since, ∣x−5∣≥0⟹−∣x−5∣≤0

⟹2−∣x−5∣≤2⟹f(x)≤2

Hence, range of f(x) is (−∞,2].

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