The range of f(x)= x² + x +1
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Answer:
For such questions, first complete the squares. The answer would be simpler than you think.
y=x2−x−1=(x−1/2)2−1/4−1=(x−1/2)2−54
ymin=−5/4 when x=1/2
ymax→∞ when x→∞
Range =[−5/4,∞)
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The range of the function f(x) = x² + x + 1 is [1,∞).
Closed bracket → [ and ]
Open bracket → ( and )
This function can give output of any real number ranging from 1 to ∞.
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