Math, asked by Rance14, 1 year ago

The range of function sin inverse (x²+2x) , x>0 ?

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Answered by 15121115anil
4
answer is option (A)

sin^-1( x^2+2x)
here x>0 .....(1)
also we find that
domain of function
and we get
x £ [ -1 , 1] ...( 2 )
then common domain from equation (1) & (2)
x £ [0, 1]
so range of the function
Y £ [ -Π/2 , Π/2]

## hope it can help you ##

Rance14: thnx man
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