The
range of
projectile at fired at an angle of
15° is 50m
if it is fired
with the
Same speed at an angle of 45° it's range
will be
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Answer:
The range of a projectile fired at an angle of 15∘ is 50 m. If it is fired with the same speed at an angle of 45∘ its range will be.
Solution :
50=u2sin2×152gor u^2 /g = (50) /(sin 30^@) = (50)/(1//2) = 100R = 9u^2 sin 2 xx 45^2)/g = u^2/g = 100 m
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