Question

The range of projectile the when launched at an angle of 25° with the horizontal is 1500
meters, what is the range when launched angle is 65°?
a. 1.5km
b. 3km
C.4.5km d. 6km
e. NOT​

Answer 1

Answer:

n= angle of projectile

Explanation:

range = u^2 sin 2 n/g

in first case

1500=  u^2 sin 2 *25/g

1500/sin 50=u^2/g

in second  case

r= 1500/sin 50* sin 65*2

= 1500/sin 50 *sin 130

50and 130 are complementary angles

range is same

r= 1500 m for 65