Question

the range of projectile when fired at an angle of 15° with the horizontal is 1.5 km . What is the range of the projectile when fired at an angle of 45° to the horizontal​

Answer 1

Answer:

Answer

Correct option is

B

3.0 km

Here in first case, R

1

=1.5,θ=15

R

1

=

g

u

2

sin(2×15)

⇒1.5=

2g

u

2

⇒

g

u

2

=3

Now, for second case,

R

2

=

g

u

2

sin(2×45)

⇒R

2

=

2g

u

2

=3km