The range of the function f(x) =
√3x²-4x+5 is
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HERE IS YOUR ANSWER
f(x) is defined if 3x2−4x+5>0
⇒3[x2−34x+35]>0⇒3[(x−32)2+911]>0
which is true for all real x
∴ Domain f(x)=(−∞,∞)
Let y=3x2−4x+5⇒3x2−4x+(5−y2)=0
For x to be real
16−12(5−y2)≥0⇒y≥311
∴ Range of f(x)=[311,∞)
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