Math, asked by punithan2307, 2 months ago

The range of the function f(x) =
√3x²-4x+5 is​

Answers

Answered by shahtamu111
1

Step-by-step explanation:

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HERE IS YOUR ANSWER

f(x) is defined if 3x2−4x+5>0

⇒3[x2−34x+35]>0⇒3[(x−32)2+911]>0

which is true for all real x

∴ Domain f(x)=(−∞,∞)

Let y=3x2−4x+5⇒3x2−4x+(5−y2)=0

For x to be real

16−12(5−y2)≥0⇒y≥311

∴ Range of f(x)=[311,∞)

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