Question

The range of the function f(x)=sgn(x- x )+1 is (where . is the greatest integer function)​

Answer 1

Given:

The function $f(x)= sgn(x^2- x )+1$.

To Find :

The range of the function  $f(x)= sgn(x^2- x )+1$ is (where x is the greatest integer function)​ ?

Solution:

Here, given function is-

$f(x)= sgn(x^2- x )+1$

Since, we know that signum function always have a range {-1,1}.

Therefore, here given function have range of {0,2}.