Math, asked by roy179266, 10 months ago

The range of the function f(x) = sin(sin inverse [x^2-1) is

(a) {.., -2, -1,0,1,2,...}

(b) {-1,0, 1}

(c) {-1,0}

(d) {-1,1}

Answers

Answered by Anonymous

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f(x)=sin(sin inverse x²-1)

here

=sin(sin inverse x²-1)

=>x²-1=0

=>x²=1

=>x= +1(or)-1

{-1,1}

(d)is the answer

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The range of the function f(x) = sin(sin inverse [x^2-1) is (a) {.., -2, -1,0,1,2,...}(b) {-1,0, 1}(c) {-1,0}(d) {-1,1}​

Answers

The range of the function f(x) = sin(sin inverse [x^2-1) is

(a) {.., -2, -1,0,1,2,...}

(b) {-1,0, 1}

(c) {-1,0}

(d) {-1,1}