Math, asked by varun253795, 8 months ago

The range of the function f(x)=

sqrt of x²-1

Answers

Answered by akshay241480
4

Answer:

Range=R (Real number)

Step-by-step explanation:

Given,

y =  \sqrt{ {x}^{2} - 1 }

So,

 {y}^{2}  =  {x}^{2}  - 1

x =  \sqrt{ {y}^{2} + 1 }

So, y can have any real values.

Hence, range=R

Answered by adithyapillai05
5

Answer:

real number is the answer

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