The range of the function f(x)=x2 + 2x + 2 is
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hope ur eq is
y=x^2+2x+2
now
write the eq like
f(x)=x^2+2x+1+1
f (x)=(x^2+2x+1)+1
f (x)=(x+1)^2+1
now
since (x+1)^2>=0 /*means always positive*/
so (x+1)^2+1>=1 /*adding 1 both side*/
f (x)>=1
so the range of f (x) will be
[1, +ve infinity )
hope it will help you
y=x^2+2x+2
now
write the eq like
f(x)=x^2+2x+1+1
f (x)=(x^2+2x+1)+1
f (x)=(x+1)^2+1
now
since (x+1)^2>=0 /*means always positive*/
so (x+1)^2+1>=1 /*adding 1 both side*/
f (x)>=1
so the range of f (x) will be
[1, +ve infinity )
hope it will help you
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