Math, asked by vamsikarthik102, 10 days ago

the range of the function f(x)=x3-8/x-2

Answers

Answered by rajunaga110
0

Step-by-step explanation:

(x^3-8)/(x-2)= (x-2)(x^2+2x+4)/(x-2)

by using a^3-b^3 = (a-b) (a^2+ab+b^2)

so

(x-2)(x^2+2x+4)/(x-2) = (x^2+2x+4)

= (x+2)^2

means what ever the value of x you always going to get positive values so

range is z+

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