Physics, asked by shantanusarnaik, 10 months ago

The range of the particle which is projected at
an angle of 15° is 1.5 km. What will be the
range for an angle of projection 45°
#

Answers

Answered by mohit1234ladwa

0

Answer:Answer:

R = v2sin2θ/g

R α sin2θ

R2/R1 = sin90/sin30

R2 = 1.5 km x 2 = 3 km.

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