Physics, asked by alyg, 4 months ago

the range of two projectiles launched from ground with the same initial velocity u and angles of projection theta 1 and theta 2 are equal .the ratio of maximum heights reaches by them is h1/h2 =1/3 .the range of projectiles R is equal to

a. u²/2g
b. 2u²/ g
c. u² /4g
d. √3u²/2g

plz tell the answer​

Answers

Answered by roshnimourya25062006
0

Answer:

dlydyxgmxgkoszmmzkgdkdigxgdo5rxks57

Answered by Anonymous
1

Explanation:

√3u2/2g your answer this.. .

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