Question

The range of x+2/2x^2+3x+6 =​

Answer 1

Answer:

⇒ 2yx2 + 3yx + 6y = x + 2 ⇒ 2yx2 + (3y – 1) x + 6y – 2 = 0 ∴ x is real D ≥ 0 ⇒ (3y – 1)2 – 8y (6y – 2) ≥ 0 ⇒ (3y – 1) (13y + 1) ≤ 0 y ∈ [- 1/13, 1/3]

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