Question

The rank of the matrix ( Veft [\begin{array} 2 &-1&0/}0 & 1 & 0 / 0 &0/end{array} \right]​

Answer 1

Step-by-step explanation:

Concept:

Rearrange the rows with leading zeroes on the left and convert into echelon form

Rank of the matrix = number of non-zeroes row in the echelon form

Calculation:

Given:

R1 → R1 + R2

R3 → R3 - 2R2

R2 → R2 – R1

R4 → R4 - R3

R3 → R3 - R1

Now it is in Echelon form

Rank of the matrix = number of non-zero rows = 2