Question

The rate constant for a first order reaction at 25°C is 0.24 s⁻¹. If the energy of activation of the reaction is 88 kJ mol⁻¹, at what temperature would this reaction have rate constant of 4 x 10⁻² s⁻¹.

Answer 1

Explanation:

log k2/k1 = ea/ 2.303 R ( T2 -T1)

log 4/24 = 88 x 10-3 / 2.303 x 8.314 ( t / 298 - 1/t2 )

T2 = 293.7k