Question

The rate constant for a reaction at 500°C is 1.6 x 10³ M⁻¹ s⁻¹. What is the frequency factor of the reaction if its energy of activation is 56 kJ mol⁻¹.​

Answer 1

Answer:

We know that,

k=A×e

RT

−E

a

Given E

a

=56kJ mol

−1

k=1.6×10

3

M

−1

s

−1

T=500+273=773K

Substituting the values,

1.6×10

3

=A×e

8.314×773

56×1000

A=0.26s

−1