The rate constant for a second order reaction is 3.33×10^-2 L mol^-1 s^-1 . The initial concentration of the reaction is 0.5 mol/L calculate the half- life of the reaction
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Answer:
0.95 min
Explanation:
t half for second order+ 1/(k*[INITIAL CONCENTRATION]=1/(0.033*0.5)=60.60SECOND IN SECONDS
=1/(0.033*0.5)*60
=1.01 min
= closest equal 0.95 min
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