Question

The rate constant for the first order decomposition of a certain reaction is described by the equation logk(s1)=14.341.25104kt (a) what is the energy of activation for the reaction

Answer 1

Answer:

The rate constant for the first order decomposition of a certain reaction is described by the equation.

ln K=14.34-$\frac{1.25*10^{4} }{T}$

also we have ln K=ln A-$\frac{E_{a} }{RT}$

so comparing these two $\frac{E_{a} }{R} =1.25*10^{4}$

$E_{a} =1.25*10^{4} *Rcalmol^{-1}$

=$1.25*10^{4} *1.987calmol^{-1}$

$E_{a} =24.83kcalmol^{-1}$