The rate constant for the first order reaction is 40 s¹. How much time will it take to reduce the initial concentration to 1/8 th value.
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The rate constant for a first order reaction is 60's 1 How much time will it take to reduce the concentration of reactant to 1 16 th of its initial value
We are given the value of rate constant for a first order reaction as 60 s−1. As a result, it will take 4.62×10−2s to reduce the initial concentration of the reactant to its 1/16th value.
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Explanation:
Given that the rate constant for a first order reaction is 60 s
−1
.
Let a M be the initial concentration.
Final concentration will be
16
a
M.
Rate constant, k=60/s
t=
k
2.303
log(
[A]
[A]
0
)
t=
60
2.303
log
⎝
⎛
16
a
a
⎠
⎞
t=4.6×10
−2
seconds
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