The rate constant for the first order reaction is 60 s^-1 how much time will it take to reduce the concentration of the reactant to 1/16 m value
Answers
Answered by
2
Explanation:
Given that the rate constant for a first order reaction is 60 s
−1
.
Let a M be the initial concentration.
Final concentration will be
16
a
M.
Rate constant, k=60/s
t=
k
2.303
log(
[A]
[A]
0
)
t=
60
2.303
log
⎝
⎜
⎛
16
a
a
⎠
⎟
⎞
t=4.6×10
−2
seconds
Similar questions