The rate constant for the reaction at 200 kelvin is 10 times less than at 400 kelvin what is the activation energy of the reaction
Answers
Answered by
1
Explanation:
C1= rate constant at temperature 200k
C2= rate constant at temperature 400k
Given that,
C1= C2/10
T1= lower temperature = 200k
T2= higher temperature = 400k
Q= activation energy
R= gas constant
The relation between activation energy , temperature and rate constant is given as
In (C2/C1)= (Q/R) [(1/T2) - (1/T1)]
inserting the above values in the equation
In (C2/10) = -(Q/R) [(1/400) - (1/200)]
In (10) = -(Q/R) [(1/400) - (1/200)]
2.303 = -(Q/R) [(1/400) - (1/200)]
Q/R = 921
Q = 921 R
Similar questions