Question

The rate constant of a first order reaction is
4 x 10-3 sec). At a reactant concentration of
0.02 M, the rate of reaction would be (Mocak-95​

Answer 1

Answer:  $8\times 10^{-5}mol/Lsec$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

As the order of the reaction is 1:

Thus rate law for a hypothetical reaction: $A\rightarrow B$ is:

$Rate=k[A]^1$

k= rate constant

[A] = concentration of A

Putting in the values we get:

$Rate=4\times 10^{-3}\times [0.02]^1$

$Rate=8\times 10^{-5}mol/Lsec$

Thus the rate of reaction would be $8\times 10^{-5}mol/Lsec$

Answer 2

Answer:r=k(A)

r=4×10-3× 0.02

Gives

r=8×10-5Msec-1

Explanation: