Chemistry, asked by rahulbadrinath363, 11 months ago

The rate constant of a reaction at 500k and 700k are 0.02 s-1 and 0.07 s-1 respectively the value of activation energy is (in KJ)​

Answers

Answered by nd8247245
0

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Answered by Draxillus
0

Concept :- Rate constant (k) is relates to activation energy Ea by the equation :-

k = A {e}^{ \frac{ - Ea}{RT} }

where,

A = Arrhenius constant.

SOLUTIONS :-

At 500 K , K = 0.02

0.02 = A {e}^{ -  \frac{Ea}{500R} } .....(1)\\ at \: 700k \\ 0.07 = A {e}^{ -  \frac{Ea}{700R} }......(2) \\ divinding \: equation(2) \: by \: (1) \\  \frac{0.07}{0.02}  \:  =  \frac{ \:A {e}^{ -  \frac{Ea}{700r} }}{ \:A{e}^{ -  \frac{Ea}{500R} }}  \\   \\  =  >  \frac{7}{2}  =  {e}^{  \frac{Ea}{500R}  -  \frac{Ea}{700R}  }  \\  \\  =  >  \frac{7}{2}  =  {e}^{ \frac{ 200Ea}{3500R} }  \\  \\  =  >  ln( \frac{7}{2} )  =  \frac{ 200Ea}{3500R}  \\  \\  =  >  ln( \frac{7}{2} )  =  \frac{2Ea}{35R}  \\  \\  =  > Ea =  \frac{35R}{2}  ln( \frac{7}{2} ) \\  \\  =  > Ea = 182.27 \\  \\  =  > Ea = 0.18227 \: kj

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