Question

The rate constant of a reaction at 500k and 700k are 0. 02S-1 and 0. 07S-1 respectively. Calculate the values of Ea and A

Answer 1

Answer :-

Ea - 18228kJ

A - 1.6 s^-1

log (k2/k1) =Ea /2.303 x R x (1/T1 -1/T2)

∴ log(.07/.02) = Ea/2.303 x 8.314 x (1/500-1/700)

Solving above we get, Ea = 18228kJ

Now, k = Ae^( -Ea/RT )

0.02 = A e^ ( - 18228 / 8.314 x 500)

Solving above we get, A = 1.6 s^-1