Question

The rate constant of a reaction is 0.33 x10-2mole
(per litre per second. If the initial concentration of
reactantis 2 then, the half-life of the reaction is

​

Answer 1

Answer:

Correct option is

D

347 s

For first order reaction,

A⟶B

Rate =k×[A]

Given, rate =2.0×10

−5

molL

−1

s

−1

[A] = Conc. of A = 0.01 M

So, 2.0×10

−5

=k×0.01

k=

0.01

2.0×10

−5

s

−1

=2.0×10

−3

s

−1

For first order reaction,

t

1/2

=

k

0.693

=

2.0×10

−3

0.693

=346.5=347s