The rate constant of a reaction is 1.5 x 10⁷ S-1 at 50°C and 4.5 x 10⁷ S-1 at 100°C. The value of energy of activation is [ ]
a) 2.2 x 10⁴ J mol-1
b) 3.3 x 10⁴ J mol-1
c) 1.1 x 10³ J mol-1
d) 10³ J mol-1
Answers
Answered by
2
Explanation:
ANSWER
log
10
k
1
k
2
=
2.303R
E
a
(
T
1
1
−
T
2
1
)
log
10
1.5×10
7
4.5×10
7
=
2.303×8.314
E
a
(
323
1
−
373
1
)
E
a
=2.2×10
4
J/mol
We know that,
log
10
k=log
10
A−
2.303RT
E
a
log
10
(1.5×10
7
)=log
10
A−
2.303×8.314×323
2.2×10
4
A=5.42×10
10
s
−1
Answered by
8
Answer:
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